Finding F(4) Given Composite Functions: A Step-by-Step Guide

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Let's dive into solving a classic problem involving composite functions. Composite functions might sound intimidating, but they're really just a way of combining two functions. This article will break down the problem step by step, making it easy to understand even if you're just starting out with functions. We're given two functions: g(x)=x+2{g(x) = x + 2} and (f∘g)(x)=x2+4{(f \circ g)(x) = x^2 + 4}. Our mission is to find the value of f(4){f(4)}. This means we need to figure out what the function f{f} does to the input 4. So, grab your thinking caps, and let's get started!

Understanding Composite Functions

Before we jump into the solution, let's make sure we're all on the same page about what composite functions are. A composite function, denoted as (f∘g)(x){(f \circ g)(x)}, means we're plugging the function g(x){g(x)} into the function f(x){f(x)}. In other words, we first apply the function g{g} to x{x}, and then we take the result and plug it into the function f{f}. Think of it like a machine where you first process something with one tool and then immediately feed it into another tool. The order matters! (f∘g)(x){(f \circ g)(x)} is generally not the same as (g∘f)(x){(g \circ f)(x)}. In our case, we know what (f∘g)(x){(f \circ g)(x)} is, and we need to use this information to figure out something about f(x){f(x)} on its own.

The key idea here is recognizing that (f∘g)(x)=f(g(x)){(f \circ g)(x) = f(g(x))}. So, whenever you see (f∘g)(x){(f \circ g)(x)}, you can replace it with f(g(x)){f(g(x))}. This notation makes it clear that we're taking the output of g(x){g(x)} and using it as the input for f(x){f(x)}. Understanding this relationship is crucial for solving problems involving composite functions. It's all about breaking down the problem into smaller steps and understanding how each function is acting on the input.

The Strategy: Working Backwards

Okay, so we know (f∘g)(x)=x2+4{(f \circ g)(x) = x^2 + 4}, and we want to find f(4){f(4)}. The trick here is to try and find a value of x{x} such that g(x)=4{g(x) = 4}. Why? Because if we can find such an x{x}, then we'll have f(g(x))=f(4){f(g(x)) = f(4)}, and we know what f(g(x)){f(g(x))} is equal to (it's x2+4{x^2 + 4}). This is a classic problem-solving technique: try to relate what you know to what you want to find. By finding an x{x} that makes g(x)=4{g(x) = 4}, we can directly connect f(g(x)){f(g(x))} to f(4){f(4)}.

In essence, we are trying to manipulate the given information to isolate f(4){f(4)}. Since we have the composite function f(g(x)){f(g(x))}, we need to find a way to make the inner function g(x){g(x)} equal to 4. This allows us to directly substitute and find the value of f(4){f(4)}. This "working backwards" strategy is incredibly useful in mathematics. Instead of trying to directly compute f(x){f(x)}, we use the properties of the composite function and the known value of g(x){g(x)} to our advantage. This often simplifies the problem significantly.

Finding the Right Value of x

So, let's find that special x{x} that makes g(x)=4{g(x) = 4}. We know that g(x)=x+2{g(x) = x + 2}. So, we need to solve the equation x+2=4{x + 2 = 4}. This is a simple algebraic equation. Subtracting 2 from both sides, we get x=4−2{x = 4 - 2}, which simplifies to x=2{x = 2}. Aha! We've found our x{x}. When x=2{x = 2}, g(x)=4{g(x) = 4}. This is a crucial step because it directly links the composite function to the value we want to find, f(4){f(4)}.

Now that we know x=2{x = 2} gives us g(x)=4{g(x) = 4}, we can substitute this value into the composite function. Remember, we know that (f∘g)(x)=x2+4{(f \circ g)(x) = x^2 + 4}. So, when x=2{x = 2}, we have (f∘g)(2)=22+4{(f \circ g)(2) = 2^2 + 4}. But we also know that (f∘g)(2)=f(g(2)){(f \circ g)(2) = f(g(2))}, and g(2)=4{g(2) = 4}. Therefore, we have f(4)=22+4{f(4) = 2^2 + 4}. This substitution is the key to unlocking the value of f(4){f(4)}. By finding the appropriate x{x}, we've successfully bridged the gap between the composite function and the isolated value of f(4){f(4)}.

Calculating f(4)

Now that we know f(4)=22+4{f(4) = 2^2 + 4}, the rest is just arithmetic. We have 22=4{2^2 = 4}, so f(4)=4+4{f(4) = 4 + 4}. Adding those together, we get f(4)=8{f(4) = 8}. And that's it! We've found the value of f(4){f(4)}. It's a testament to the power of understanding composite functions and using a bit of algebraic manipulation.

Therefore, the final answer is f(4)=8{f(4) = 8}. This result confirms that by carefully working with the composite function and finding the correct input value, we can determine the value of the outer function at a specific point. Remember to always double-check your calculations and make sure your substitutions are accurate to avoid errors.

Conclusion

So, to recap, we were given g(x)=x+2{g(x) = x + 2} and (f∘g)(x)=x2+4{(f \circ g)(x) = x^2 + 4}, and we wanted to find f(4){f(4)}. We realized that we needed to find an x{x} such that g(x)=4{g(x) = 4}. We found that x=2{x = 2} satisfied this condition. Then, we substituted this value into the composite function to get f(4)=22+4=8{f(4) = 2^2 + 4 = 8}. Therefore, f(4)=8{f(4) = 8}.

This problem illustrates a common technique in mathematics: using given information and strategic manipulation to find unknown values. Understanding composite functions and practicing these problem-solving strategies will help you tackle more complex problems in the future. Remember, math is all about breaking down problems into manageable steps and understanding the relationships between different concepts. Keep practicing, and you'll become a pro at solving these types of problems!

I hope this breakdown helped you understand how to solve this type of problem. Keep practicing and you'll get the hang of it in no time! Good luck, guys!